Hola
en el problema
primero restamos
[tex]3x + 9 = x + 15 \\ 3x + 9 = x + 15 - 9 \\ 3x = x + 6 \\ 3x - x = x + 6 \\ 2x = 6[/tex]
Dividir
[tex] \frac{2x}{2} \\ 2x \div 2 = \frac{6}{2} = 3[/tex]
[tex] \bf \pink{x = 3}[/tex]
Respuesta:
[tex] \large \boxed { \bold{x = 3}}[/tex]
3x + 9 = x + 15
3x - x = 15 - 9
2x = 6
x = 6/2
x = 3
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Verified answer
Hola
en el problema
primero restamos
[tex]3x + 9 = x + 15 \\ 3x + 9 = x + 15 - 9 \\ 3x = x + 6 \\ 3x - x = x + 6 \\ 2x = 6[/tex]
Dividir
[tex] \frac{2x}{2} \\ 2x \div 2 = \frac{6}{2} = 3[/tex]
[tex] \bf \pink{x = 3}[/tex]
Respuesta:
[tex] \large \boxed { \bold{x = 3}}[/tex]
3x + 9 = x + 15
3x - x = 15 - 9
2x = 6
x = 6/2
x = 3