Respuesta:
Es 1 espero te sea de ayuda!
Explicación paso a paso:
√36×1⁶+5³÷25-³√125×2
6×1+125÷25-5×2
6+5-10= 1
[tex] \sqrt{36} \times {1}^{6} + {5}^{3} \div 25 - \sqrt[3]{125} \times 2 = 1[/tex]
[tex]\boxed{HoLa}[/tex]
[tex] \sqrt{36} \times {1}^{6} + {5}^{3} \div 25 - \sqrt[3]{125} \times 2 = \\ \\ 6 \times {1}^{6} + {5}^{3} \div 25 - ( \sqrt[3]{125} {)}^{1} \times 2 = \\ \\ 6 \times 1 + {5}^{3} \div 25 - ( \sqrt[3]{125} {)}^{1} \times 2 = \\ \\ 6 + {5}^{3} \div 25 - ( \sqrt[3]{125} {)}^{1} \times 2 = \\ \\ 6 + 125 \div 25 - ( \sqrt[3]{125} {)}^{1} \times 2 = \\ \\ 6 + 5 - ( \sqrt[3]{125} {)}^{1} \times 2 = \\ \\ 11 - ( \sqrt[3]{125} {)}^{1} \times 2 = \\ \\ 11 - 5 \times 2 = \\ \\ 11 - 10 = \\ \\ 1[/tex]
Si te sirvió deja tu corona :)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
Respuesta:
Es 1 espero te sea de ayuda!
Explicación paso a paso:
√36×1⁶+5³÷25-³√125×2
6×1+125÷25-5×2
6+5-10= 1
[tex] \sqrt{36} \times {1}^{6} + {5}^{3} \div 25 - \sqrt[3]{125} \times 2 = 1[/tex]
[tex]\boxed{HoLa}[/tex]
Explicación paso a paso:
[tex] \sqrt{36} \times {1}^{6} + {5}^{3} \div 25 - \sqrt[3]{125} \times 2 = \\ \\ 6 \times {1}^{6} + {5}^{3} \div 25 - ( \sqrt[3]{125} {)}^{1} \times 2 = \\ \\ 6 \times 1 + {5}^{3} \div 25 - ( \sqrt[3]{125} {)}^{1} \times 2 = \\ \\ 6 + {5}^{3} \div 25 - ( \sqrt[3]{125} {)}^{1} \times 2 = \\ \\ 6 + 125 \div 25 - ( \sqrt[3]{125} {)}^{1} \times 2 = \\ \\ 6 + 5 - ( \sqrt[3]{125} {)}^{1} \times 2 = \\ \\ 11 - ( \sqrt[3]{125} {)}^{1} \times 2 = \\ \\ 11 - 5 \times 2 = \\ \\ 11 - 10 = \\ \\ 1[/tex]
Si te sirvió deja tu corona :)