Akar 3^x+3=(1/3)^6-x
hanifahrsbnptr
Akar 3^x+3=(1/3)^6-x 3^x/2 + 3/2 = (1/3)^6-x 3^x+3/2 = (3^-1)6-x 3^x+3/2 = 3^-6+x x+3/2 = -6 + x x + 3 = -12+2x x-2x = -12-3 -x = -15 x = 15
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