Question

35. Perhatikan gambar berikut! G2 cm G A 4 cm 10 с 5 cm B 10 10 cm F Hitunglah luas permukaan bangun ruang tersebut! HOTS Jawab:​

Answer 1

[tex]c = \sqrt{ {t}^{2} + (a - b) {}^{2} } = \sqrt{ {4}^{2} + (5 - 2) {}^{2} } \\ c = \sqrt{ {4}^{2} + {3}^{2} } = \sqrt{16 + 9} = \sqrt{25} = 5 \\ \\ lp \: prisma \: trapesium \: siku - siku \\ (a + b)(tt + tp) + tp(c + tt) \\ (5 + 2)(4 + 10) + 10(5 + 4) \\ 7(14) + 10(9) \\ 98 + 90 \\ 188 \: {cm}^{2} [/tex]

Answer 2

C = √4² + (5 - 2)²

= √(4(4) + 3²

= √16 + 9

= √25

= √5²

= 5 CM

MAKA :

LP :

= (5 + 2) × (4 + 10) + (10 × (5 + 4)

= (7 × 14) + (10 × 9)

= 98 + 90

= 188 CM²