Question

Bentuk sederhana dari (27a^-5 b^-3 / 3^5 a^-7 b^-5 )^-1

keterangan : ^ = pangkat

Answer 1

(27a^-5 b^-3 / 3^5 a^-7 b^-5 )^-1
= ((3^(3-5) a^(-5-(-7)) b^(-3-(-5)))^-1
= (3^-2 a^2 b^2)^-1
= 1/(3^-2 a^2 b^2)
= 3^2/(a^2 b^2)