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3x+4y=7 (×1) 3x+4y=7
8x-2y=6 (×2) 16x-4y=12 +
___________
19x = 19
x = 19 / 19
x = 1
# substitusi
3x+4y=7
3 (1)+4y=7
4y = 7-3
4y = 4
y = 4/4
y = 1
HP { 1 , 1}
thanks
3x + 4y = 7 dikali 8
8x-2y=6 dikali 3
24x+ 32y=56
24x -6y =18 dikurangkan
38y=38
y=38/38=1
subtitusikan
3x + 4(1) =7
3x=7-4
x=3/3=1