Question

1. jika x = √7 - √5 per √7+√5 dan y = √7 +√5 per √7 + √5
maka nilai x + y adalah

2. 243^3x-2 = (√81)^6x+9

3. 9^x-1 = (1/3)^4x-2

Answer 1

1)√7 - √5 per √7+√5 + √7 +√5 per √7 + √5 (7-5) + (7+5) per 7+5 2 + 12 per 12 = 14/12 = 1,17 2) 243^3x-2 = (√81)^6x+9 (3^5)^3x-2 = 9^6x+9 (3)^15x-2 = (3²)^6x+9 (3)^15x-2 = (3)^12x+18 15x - 2 = 12x + 18 15x - 12x = 18 + 2 3x = 20 X = 20/3 x = 6,67 3) 9^x-1 = (⅓)^4x-2 (⅓^-2)^x-1 =(⅓)^4x-2 (⅓)^-2x+2 =(⅓)^4x-2 -2x + 2 = 4x - 2 -2x - 4x = -2 - 2 -6x = -4 x = -4/-6 x = 0,67