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(1/3)x - (7/2)x = (5/2) - (2/3)
(-19/6)x = (11/6)
(11/6)
x = --------
(-19/6)
x=( -11/ 19)
• (1/3 ) - x = 2 - (5/3) - x Algo esta mal escrito en esta no se, pero las x se me canselan
(1/3 - 2 + 5/3) = -x + x
(2/3) = 0
• (2/Z ) - 1 + (2 /5) = 4Z - 1
(2/Z) - (4Z) = ( - 2/5) - 0
(2 - 4 Z^2 )
---------------- = (- 2/5)
z
(2 - 4z^2 ) = (- 2/5)z
(-4z^2 ) + ( 2/5 z) + 2 = 0
multiplicando por (-1) toda la ecuacion
4Z^2 - 2/5 Z - 2 =0
Por formula general de una ecuacion cuadratica =
Z1= 0.7588
Z2= -0.6588