Question

Keliling sebidang kebun 280 meter.Jika panjang kebun = 1 1/3 x lebarnya, berapakah cm2 luas kebun tersebut ?

Answer 1

Keliling = 2p + 2l
= 2 (p+l)

1 1/3 = 4/3

p = 4/3, l = 1
Jumlah perbandingan = 4/3 + 1 = 7/3

L = 1 / (7/3) * 280/2
= 60 meter

P =  4/3 * 60
= 80 meter

luas kebun = LP
= 60 * 80
= 4800 m²
= 48000000 cm²

Answer 2

K = 280 m, p = 1/3 l
K = 2 (P + l)
280 = 2 (1/3 l + l)
280 = 2 ( 4/3 l)
280 = 8/3 l
l = 105 m
p = 1/3 l
   = 1/3 x 105
   = 35 m

L = p x l
   = 35 x 105
   = 3675 m2
   = 3675 x 10^4  cm2