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f(b) = b+2
2/3b+b = b+2
2/3b+b-b = 2
2/3b = 2
2b = 6
b = 3
f(-b) = f(-3)
= 2/3(-3) + 3
= -2+3
= 1
jawab: C
f(b) = b + 2
b + 2 = (2/3)b + b
b + 2 = (5/3)b
b - (5/3)b = - 2
(-2/3)b = - 2
b = 3
f(x) = (2/3)x + 3
f(-b) = f(-3) = (2/3)(-3) + 3
= - 2 + 3
= 1