Benny, Denny, Jenny and Penny competed against each other during a Math challenge. The average number of questions completed by the 4 of them was 81. The number of questions completed by Benny was 2/3 the number of questions completed by Denny. Jenny completed 6 more questions than Denny. Penny completed 78 questions. How many questions did Jenny complete?
Let's use algebra to solve the problem. Let's assume the number of questions completed by Denny is "D."
We are given the following information:
1. The average number of questions completed by all four of them is 81. So, the sum of their completed questions is 81 * 4 = 324.
2. Benny completed 2/3 the number of questions completed by Denny. So, Benny completed (2/3)D questions.
3. Jenny completed 6 more questions than Denny. So, Jenny completed D + 6 questions.
4. Penny completed 78 questions.
Now, let's add up the number of questions completed by each person:
Benny + Denny + Jenny + Penny = (2/3)D + D + (D + 6) + 78
According to the first piece of information, the total number of questions is 324:
(2/3)D + D + (D + 6) + 78 = 324
To solve for D, let's combine like terms:
(2/3)D + D + D + 6 + 78 = 324
(8/3)D + 84 = 324
Now, let's isolate D:
(8/3)D = 324 - 84
(8/3)D = 240
Next, divide both sides by 8/3 to solve for D:
D = 240 / (8/3)
D = 240 * (3/8)
D = 90
Now that we have the number of questions completed by Denny (D = 90), we can find the number of questions completed by Jenny:
Jenny = D + 6 = 90 + 6 = 96
So, Jenny completed 96 questions.
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