October 2018 1 31 Report
Diketahui sin a = 2/3, sudut a lancip. Tentukan nilai dari cos a + 2 tan a
\displaystyle \sin a=\frac23\\\frac{a}{c}=\frac23\\\\a=2\\c=3\\b=\sqrt{c^2-a^2}=\sqrt{3^2-2^2}=\sqrt{9-4}=\sqrt{5}\\\\\cos a+2\tan a=\frac{b}{c}+\frac{2a}{b}\\\cos a+2\tan a=\frac{b^2+2ac}{cb}\\\cos a+2\tan a=\frac{(\sqrt5)^2+2\times2\times3}{3\times\sqrt5}\\\cos a+2\tan a=\frac{5+12}{3\sqrt5}\\\cos a+2\tan a=\frac{17}{3\sqrt5}\\\boxed{\boxed{\cos a+2\tan a=\frac{17}{15}\sqrt5}}
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