Question

Sebuah persegi panjang ABCD, diketahui sudut C=3Y; sudut A=X+10; Y=1/2 X; sudut B=4/3 sudut A, cari nilai X, Y, dan sudut B

Answer 1

C = 3y
90° = 3y
y = 30°

y = 1/2 x
30 = 1/2 x
x = 30(2)
x = 60

A = x + 10
A = 60 + 10
A = 70°

B = 4/3 A
B = 4 x 70 / 3
B = 280 / 3
B = 93.3°

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