pueden resolver esto por mi
determina el valor de la incognita
si X/2=Y/3 siendo X mas Y =10
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x = y .......3x=2y
2 3
sustituimos x=10-y,en la segunda ecuacion
3x=2y
3(10-y)=2y
30-3y=2y
-3y-2y= -30
-5y= -30
y= -30/-5
y=6
si y=6........x+y=10....x+6=10....x=10-6.....x=4
x=4 y=6