Jawaban:
3. 2x + 3y = 12 ... (1)
3x + 2y = 8 ... (2)
Eliminasi y pers 1 dan 2
2x + 3y = 12 |x2| 4x + 6y = 24
3x + 2y = 8 |x3| 9x + 6y = 24 -
5x = 0
[tex]x = \frac{0}{5} [/tex]
X = 0
Substitusi x=0 ke pers 1
2x +3y = 12
2(0) + 3y = 12
0 + 3y = 12
3y = 12
[tex]y = \frac{12}{3} [/tex]
y = 4
Nilai a + b = 0 + 4 = 4
Jawabannya D. 4
4. y = 4x - 11
4x - y = 11 ... (1)
3y = -2x - 5
-2x -3y = 5 ... (2)
4x - y = 11 |x3| 12x - 3y = 33
-2x - 3y = 5 |x1| -2x - 3y = 5 -
14x = 28
x = 28/14
X = 2
Substitusi x=2 ke pers 1
4x - y = 11
4(2) - y = 11
8 - y = 11
-y = 11 - 8
-y = 3
y = -3
Hp{2, - 3}
Jadi, titik potongnya adalah c. (2,-3)
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Jawaban:
3. 2x + 3y = 12 ... (1)
3x + 2y = 8 ... (2)
Eliminasi y pers 1 dan 2
2x + 3y = 12 |x2| 4x + 6y = 24
3x + 2y = 8 |x3| 9x + 6y = 24 -
5x = 0
[tex]x = \frac{0}{5} [/tex]
X = 0
Substitusi x=0 ke pers 1
2x +3y = 12
2(0) + 3y = 12
0 + 3y = 12
3y = 12
[tex]y = \frac{12}{3} [/tex]
y = 4
Nilai a + b = 0 + 4 = 4
Jawabannya D. 4
4. y = 4x - 11
4x - y = 11 ... (1)
3y = -2x - 5
-2x -3y = 5 ... (2)
Eliminasi y pers 1 dan 2
4x - y = 11 |x3| 12x - 3y = 33
-2x - 3y = 5 |x1| -2x - 3y = 5 -
14x = 28
x = 28/14
X = 2
Substitusi x=2 ke pers 1
4x - y = 11
4(2) - y = 11
8 - y = 11
-y = 11 - 8
-y = 3
y = -3
Hp{2, - 3}
Jadi, titik potongnya adalah c. (2,-3)