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b) (400 K − 273.15) × 9/5 + 32 = 260.33 °F
c) 200 °C + 273.15 = 473.15 K
d) (-240 °F − 32) × 5/9 + 273.15 = 122.039 K
e) 146 K − 273.15 = -127.1 °C