[tex]a)\ \ 4\dfrac{1}{3}\cdot\dfrac{9}{13}=\dfrac{\not13^1}{\not3_{1}}\cdot\dfrac{\not9^3}{\not13_{1}}=3\\\\\\b)\ \ 5\dfrac{4}{9}:1\dfrac{3}{4}=\dfrac{49}{9}:\dfrac{7}{4}=\dfrac{\not49^7}{9}\cdot\dfrac{4}{\not7_{1}}=\dfrac{28}{9}=3\dfrac{1}{9}\\\\\\c)\ \ \dfrac{3}{\not5_{1}}\cdot\not10^2\cdot8\dfrac{1}{3}=3\cdot2\cdot\dfrac{25}{3}=\not6^2\cdot\dfrac{25}{\not3_{1}}=2\cdot25=50[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
[tex]a)\ \ 4\dfrac{1}{3}\cdot\dfrac{9}{13}=\dfrac{\not13^1}{\not3_{1}}\cdot\dfrac{\not9^3}{\not13_{1}}=3\\\\\\b)\ \ 5\dfrac{4}{9}:1\dfrac{3}{4}=\dfrac{49}{9}:\dfrac{7}{4}=\dfrac{\not49^7}{9}\cdot\dfrac{4}{\not7_{1}}=\dfrac{28}{9}=3\dfrac{1}{9}\\\\\\c)\ \ \dfrac{3}{\not5_{1}}\cdot\not10^2\cdot8\dfrac{1}{3}=3\cdot2\cdot\dfrac{25}{3}=\not6^2\cdot\dfrac{25}{\not3_{1}}=2\cdot25=50[/tex]