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g(x)= (2x+4)/(3x-1)
g⁻¹{ (2x+4)/(3x-1)} = x
untuk g⁻¹(3) = ...
(2x+4)/(3x-1) = 3
3(3x-1) =2x + 4
9x - 3 = 2x + 4
9x - 2x = 4 +3
7x = 7
x = 1
,
g⁻¹(3)= 1