Jawab:
Luas = 4/3 satuan
Penjelasan dengan langkah-langkah:
Luas antara kurva dan garis
dengan rumus D√D/(6.a²)
y = x² - 3x + 2
y = x -1 ...........(kurangkan)
0 = x² - 4x + 3
a= 1 , b = - 4 , c= 3
D = b² -4ac
D = (-4)² -4(1)(3)
D = 16-12 = 4
*
L = D√D/(6.a²)
L = (4√4)/(6.1²)
L = 8/6
L= 4/3 satuan
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Jawab:
Luas = 4/3 satuan
Penjelasan dengan langkah-langkah:
Luas antara kurva dan garis
dengan rumus D√D/(6.a²)
y = x² - 3x + 2
y = x -1 ...........(kurangkan)
0 = x² - 4x + 3
a= 1 , b = - 4 , c= 3
D = b² -4ac
D = (-4)² -4(1)(3)
D = 16-12 = 4
*
L = D√D/(6.a²)
L = (4√4)/(6.1²)
L = 8/6
L= 4/3 satuan