Jawaban dan cara ada di foto. Semoga membantu :)
³log x² = 4
nilai x = 9
Pembahasan :
a'log b = c
= a'log b = a'log a^c
<=> b = a^c
a'log bⁿ = c
= n . a'log b = c
= a'log b = c/n
= a'log b = a'log a^(c/n)
<=> b = a^(c/n)
= 2 . ³log x = 4
= ³log x = 4/2
= ³log x = 2
= ³log x = ³log 3²
<=> x = 3²
= x = 9
Pelajari lebih lanjut :
brainly.co.id/tugas/3287901
Detil jawaban :
Mapel : matematika
kelas : 10
materi : logaritma
kode kategorisasi : 10.2.2.1
Kata kunci :
logaritma, nilai x, basis
#backtoschool2019
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Jawaban dan cara ada di foto. Semoga membantu :)
³log x² = 4
nilai x = 9
Pembahasan :
a'log b = c
= a'log b = a'log a^c
<=> b = a^c
a'log bⁿ = c
= n . a'log b = c
= a'log b = c/n
= a'log b = a'log a^(c/n)
<=> b = a^(c/n)
³log x² = 4
= 2 . ³log x = 4
= ³log x = 4/2
= ³log x = 2
= ³log x = ³log 3²
<=> x = 3²
= x = 9
Pelajari lebih lanjut :
brainly.co.id/tugas/3287901
Detil jawaban :
Mapel : matematika
kelas : 10
materi : logaritma
kode kategorisasi : 10.2.2.1
Kata kunci :
logaritma, nilai x, basis
#backtoschool2019