Question

1/2 log 1/16 + 3log akar 3 - 2log 1/32+ 1/3 log akar 3

Answer 1

^1/2log 1/16 + ^3log akar 3 - ^2log 1/32 + ^1/3 log akar 3
= ^2^-1 log 2^-4 + ^3log 3^1/2 - ^2log 2^-5 + ^3^-1 log 3^1/2
= -4/-1 . ^2log 2 + 1/2 . ^3log 3 - (-5) . ^2log 2 + (-1/2) . ^3log 3
= 4 + 1/2 + 5 - 1/2
= 9

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