Question

3 log 2 = m dan 2 log 7= n, maka 14 log 54 =

Answer 1

3log 2 =m 2log 7 = n maka 3log 7 =mn 14 log 54 = = 3log 54 / 3log 14 = 3log (3x3x3x2) / 3log (2x7) = 3log3 + 3log3 + 3log3 + 3log2 / 3log2 + 3log7 = 1+1+1+m / m + mn = 3 + m / m + mn

Answer 2

3log2 = m ⇒ 2log3 = 1/m
2log7 = n

maka

14log54 = (2log54)/(2log14)
              = (2log3³ + 2log2)/(2log2 + 2log7)
              = (3 · 2log3 + 1)/(1 + n)
              = (3/m + 1)/(1 + n)
              = ((m + 3)/m)/(1 + n)
              = (m + 3)/(m + mn)


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