Question

Carilah nilai dari f(0),f(1),f(-3), dan f(1/3) jika f(x)= 6x²-19x+10

Answer 1

Verified answer

F(x) = 6x² - 19x + 10

f(0) = 6(0²) - 19(0) + 10
f(0) = 0 - 0 + 10
f(0) = 10

f(1) = 6(1²) - 19(1) + 10
f(1) = 6 - 19 + 10
f(1) = -3

f(-3) = 6(-3)² - 19(-3) + 10
f(-3) = 6(9) + 57 + 10
f(-3) = 54 + 57 + 10
f(-3) = 121

f(⅓) = 6(⅓)² - 19(⅓) + 10
f(⅓) = 6(1/9) - 19/3 + 10
f(⅓) = 6/9 - 19/3 + 30/3
f(⅓) = 2/3 - 19/3 + 30/3
f(⅓) = 13/3
f(⅓) = 4 ⅓