Odpowiedź:
3. 1800m=[tex]\frac{at^2}{2}[/tex]
3600m=a[tex]t^{2}[/tex]
3600m[tex]\frac{3600m}{4m/s^2}=t^2\\ 900s^2=t^2\\t=\sqrt{900s^2} = 30s[/tex]
4.s=vt
v=s/t=[tex]\frac{17cm}{\frac{2}{7}s } =\frac{17*7cm}{2s}=59.5cm/s=0.595m/s[/tex]
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Odpowiedź:
3. 1800m=[tex]\frac{at^2}{2}[/tex]
3600m=a[tex]t^{2}[/tex]
3600m[tex]\frac{3600m}{4m/s^2}=t^2\\ 900s^2=t^2\\t=\sqrt{900s^2} = 30s[/tex]
4.s=vt
v=s/t=[tex]\frac{17cm}{\frac{2}{7}s } =\frac{17*7cm}{2s}=59.5cm/s=0.595m/s[/tex]