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Quedan 8 obreros
Hacemo regla de 3 inversa porque a mas obreros menos dias
6 Ob-----------> 1/3 d
8 Ob-----------> x
6 Ob *1/3 d / 8 Ob
x = (6/3)/8 d
x = 2/8 d Simplificando sacando mitad
x = 1/4 d
Los 8 obreros demoran 1/4 de dia.