[tex]\left(-\frac{1}{2}\right)^2=\frac{1}{4}=\frac{4}{16}\\-0,(2)=-0,22222222...\\-0,(20)=-0,20202020...\\\left(\frac{3}{4}\right)^2=\frac{9}{16}\\\left(-\frac{1}{2}\right)^3=-\frac{1}{8}=-\frac{125}{1000}=-0,125\\\left(\frac{4}{3}\right)^2=\frac{16}{9}=1\frac{7}{9}[/tex]
Uporządkujmy te liczby rosnąco (czyli od najmniejszej do największej).
[tex]-0,(2) < -0,(20) < \left(-\frac{1}{2}\right)^3 < \left(-\frac{1}{2}\right)^2 < \left(\frac{3}{4}\right)^2 < \left(\frac{4}{3}\right)^2[/tex]
Zatem
[tex]A=-0,(2)\\B=-0,(20)\\C=\left(-\frac{1}{2}\right)^3\\D=\left(-\frac{1}{2}\right)^2\\E=\left(\frac{3}{4}\right)^2\\F=\left(\frac{4}{3}\right)^2[/tex]
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[tex]\left(-\frac{1}{2}\right)^2=\frac{1}{4}=\frac{4}{16}\\-0,(2)=-0,22222222...\\-0,(20)=-0,20202020...\\\left(\frac{3}{4}\right)^2=\frac{9}{16}\\\left(-\frac{1}{2}\right)^3=-\frac{1}{8}=-\frac{125}{1000}=-0,125\\\left(\frac{4}{3}\right)^2=\frac{16}{9}=1\frac{7}{9}[/tex]
Uporządkujmy te liczby rosnąco (czyli od najmniejszej do największej).
[tex]-0,(2) < -0,(20) < \left(-\frac{1}{2}\right)^3 < \left(-\frac{1}{2}\right)^2 < \left(\frac{3}{4}\right)^2 < \left(\frac{4}{3}\right)^2[/tex]
Zatem
[tex]A=-0,(2)\\B=-0,(20)\\C=\left(-\frac{1}{2}\right)^3\\D=\left(-\frac{1}{2}\right)^2\\E=\left(\frac{3}{4}\right)^2\\F=\left(\frac{4}{3}\right)^2[/tex]