Odpowiedź:
3.
m = 2 kg
ΔT = 60 K
ΔEw = 252 kJ = 252000 J
ΔEw = m*c*ΔT
c=
c= J/Kkg
NAFTA
4.
m = 0,5 kg
ΔEw = 13,125 kJ =13125 J
T1 = 100C = 373 K
T2 = 350C = 623 K
ΔT = 623 - 373 = 250 K
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Verified answer
Odpowiedź:
3.
m = 2 kg
ΔT = 60 K
ΔEw = 252 kJ = 252000 J
ΔEw = m*c*ΔT
c=![\frac{Ew}{m*T} \frac{Ew}{m*T}](https://tex.z-dn.net/?f=%5Cfrac%7BEw%7D%7Bm%2AT%7D)
c=
J/Kkg
NAFTA
4.
m = 0,5 kg
ΔEw = 13,125 kJ =13125 J
T1 = 100C = 373 K
T2 = 350C = 623 K
ΔT = 623 - 373 = 250 K
c=![\frac{Ew}{m*T} \frac{Ew}{m*T}](https://tex.z-dn.net/?f=%5Cfrac%7BEw%7D%7Bm%2AT%7D)
c=
J/Kkg
Wyjaśnienie: