❀ Planteamos la ecuación y resolvemos:
[tex] \frac{1}{5} + \frac{2}{3} + x = 1 \\ \\ \frac{15 \div 5 \times 1 + 15 \div 3 \times 2}{15} + x = 1 \\ \\ \frac{3 + 10}{15} + x = 1 \\ \\ \frac{13}{15} + x = 1 \\ \\ x = \frac{1}{1} - \frac{13}{15} \\ \\ x = \frac{15 \div 1 \times 1 - 15 \div 15 \times 13}{15} \\ \\ x = \frac{15 - 13}{15} \\ \\ x = \frac{2}{15} [/tex]
Por lo tanto, le queda 2/15 de su dinero para el taxi.
❀ Comprobamos:
[tex] \frac{1}{5} + \frac{2}{3} + x = 1 \\ \\ \frac{1}{5} + \frac{2}{3} + \frac{2}{15} = 1 \\ \\ \frac{15 \div 5 \times 1 + 15 \div 3 \times 2 + 15 \div 15 \times 2}{15} = 1 \\ \\ \frac{3 + 10 + 2}{15} = 1 \\ \\ \frac{15}{15} = 1 \\ \\ 1 = 1[/tex]
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- Solución:
❀ Planteamos la ecuación y resolvemos:
[tex] \frac{1}{5} + \frac{2}{3} + x = 1 \\ \\ \frac{15 \div 5 \times 1 + 15 \div 3 \times 2}{15} + x = 1 \\ \\ \frac{3 + 10}{15} + x = 1 \\ \\ \frac{13}{15} + x = 1 \\ \\ x = \frac{1}{1} - \frac{13}{15} \\ \\ x = \frac{15 \div 1 \times 1 - 15 \div 15 \times 13}{15} \\ \\ x = \frac{15 - 13}{15} \\ \\ x = \frac{2}{15} [/tex]
Por lo tanto, le queda 2/15 de su dinero para el taxi.
❀ Comprobamos:
[tex] \frac{1}{5} + \frac{2}{3} + x = 1 \\ \\ \frac{1}{5} + \frac{2}{3} + \frac{2}{15} = 1 \\ \\ \frac{15 \div 5 \times 1 + 15 \div 3 \times 2 + 15 \div 15 \times 2}{15} = 1 \\ \\ \frac{3 + 10 + 2}{15} = 1 \\ \\ \frac{15}{15} = 1 \\ \\ 1 = 1[/tex]