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t = (4x-3y) cm
Luas = 1/2 alas x tinggi
= (4x-3y) x (4x-3y)
= (4x-3y)²
t = 2/3 ( 4x - 3y )
Ditanyakan : L = ...?
penyelesaian
L = 1/2 . a . t
= 1/2 . ( 4x - 3y ) . { 2/3 (4x-3y) }
= 1/2 . 2/3 .(4x-3y).(4x-3y)
= 1/3 (4x-3y)^2
Jadi luas segitiga tersebut adalah 1/3.(4x-3y)^2