Question

Persamaan garis yg bergradien -1/3 dan melalui titik (1,3)adalah....
a.3x-y+10=10
b.3x-y-10=10
c.x+3y+10=0
d.x+3y-10=0
pakai cara kaPliss

Answer 1

Verified answer

Cara mengetahui persamaan garis
y-y1 = m(x-x1)
y1 = 3
x1 = 1
m = -1/3

y - 3 = -1/3 (x - 1)
y - 3 = -x/3 + 1/3
y = -x/3 + 1/3 + 3
y = -x/3 + 10/3
y = (-x+10)/3
3y = -x + 10
x + 3y = 10
x + 3y - 10 = 0

jawabannya d.