Question

Diketahui sin a cos b = 1/3 dan (a+b) = 150°,tentukan nilai sin (a-b)

Answer 1

Verified answer

Diketahui
sin a cos b = 1/3
(a+b) = 150°
maka
sin(a + b)
= sin 150°
= 1/2

2 sina . cosb = sin(a+b) - sin(a-b)
2(1/3) = 1/2 - sin(a-b)
sin(a-b) = 1/2 - 2/3
sin(a-b) = (3 - 4)/6
sin(a-b) = -1/6