Please help. 160+40+10+...=.... a.160 b.213 c.213 1/3 d.480 e.640.... Question from @fialafiatown

September 2018 1 15 Report

Please help.
160+40+10+...=....
a.160
b.213
c.213 1/3
d.480
e.640

Takamori37 Deret tak hingga,
a = 160
r = 1/4
$\displaystyle S_\infty=\frac{a}{1-r}=\frac{160}{1-\frac{1}{4}}=\frac{160}{^3/_4} \\ S_\infty=160\times \frac{4}{3}=\frac{640}{3}=213\frac{1}{3}$

2 votes Thanks 1

fialafiatown thank u so much:)

Takamori37 You're welcome...

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