V.BALOK :
= 2/3(1(10(80/10(6)
= 2/3(10(8(6)
= 2/3(10(48)
= 2/3(480)
= 2(480)/3
= 960/3
= 320 DM³
= 320 L
V.BOLA :
= 4/3πR³
= 4/3(22/7(35)³
= 4/3(22/7(42.875)
= 4/3(22(42.875/7)
= 4/3(22(6.125)
= 4/3(134.750)
= 4(134.750)/3
= 539.000/3
= 179.666,667 CM³
= 179,667 DM³
= 179,667 L
MAKA :
320 - 179,667 - 1/3(320)
= 140,33 - 320/3
= 140,33 - 106,66
= 33,67 DM³
= 33,67 L
[tex]{\color{aqua}{\boxed{\tt{CaptainInnovaGR}}\:}}[/tex]
KOREKSI
bangun ruang
balok
bola
Volume air yg tumpah
= volume bola - 1/3 volume bak
= 4/3 πr³ - 1/3 × plt
= 1/3 (4 × 22/7 × 35³ - 100 × 80 × 60) cm³
= 59000/3
= 19666,67 cm³
= 19,67 liter
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
V.BALOK :
= 2/3(1(10(80/10(6)
= 2/3(10(8(6)
= 2/3(10(48)
= 2/3(480)
= 2(480)/3
= 960/3
= 320 DM³
= 320 L
V.BOLA :
= 4/3πR³
= 4/3(22/7(35)³
= 4/3(22/7(42.875)
= 4/3(22(42.875/7)
= 4/3(22(6.125)
= 4/3(134.750)
= 4(134.750)/3
= 539.000/3
= 179.666,667 CM³
= 179,667 DM³
= 179,667 L
MAKA :
320 - 179,667 - 1/3(320)
= 140,33 - 320/3
= 140,33 - 106,66
= 33,67 DM³
= 33,67 L
[tex]{\color{aqua}{\boxed{\tt{CaptainInnovaGR}}\:}}[/tex]
KOREKSI
Verified answer
bangun ruang
balok
bola
Volume air yg tumpah
= volume bola - 1/3 volume bak
= 4/3 πr³ - 1/3 × plt
= 1/3 (4 × 22/7 × 35³ - 100 × 80 × 60) cm³
= 59000/3
= 19666,67 cm³
= 19,67 liter