rozwiąż równianie.
DAJE NAJ!!
a) 3(x-2)-2(3-x)=3x+3
b) 3-5x/2=1 - x-2/3
DAJE NAJ!!
a) 3(x-2)-2(3-x)=3x+3
b) 3-5x/2=1 - x-2/3
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
Odpowiedź w załączniku, liczę na naj :)
[tex]3(x - 2) - 2(3 - x) = 3x + 3 \\ 3x - 6 - 6 + 2x - 3x - 3 = 0 \\ 2x - 15 = 0 \\ 2x = 15 \\ x = \frac{ 15}{2} [/tex]
[tex] \frac{3 - 5x}{2} = 1 - \frac{x - 2}{ 3} ( \times 6 \\ 9 - 15x = 6 - 2x + 4 \\ 9 - 15x - 6 + 2x - 4 = 0 \\ -1 - 13x = 0 \\ - 13x = 1 \\ x = - \frac{1}{13} [/tex]