Bantuin kk
(1/3)³ ∛3⁵x+2=3 adalah..
mohon caranya kk
(1/3)³ ∛3⁵x+2=3 adalah..
mohon caranya kk
izharulhaq78
![(\frac{1}{3})^3\sqrt[5]{3^{5x+2}}=3\\\sqrt[5]{3^{5x+2}}=3\times3^3\\(\sqrt[5]{3^{5x+2}})^5=(3^4)^5\\3^{5x+2}=3^{4\times5}\\3^{5x+2}=3^{20}\\\therefore\\5x+2=20\\5x=20-2\\5x=18\\\boxed{x=\frac{18}{5}\text{ atau }3\frac{3}{5}}](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B3%7D%29%5E3%5Csqrt%5B5%5D%7B3%5E%7B5x%2B2%7D%7D%3D3%5C%5C%5Csqrt%5B5%5D%7B3%5E%7B5x%2B2%7D%7D%3D3%5Ctimes3%5E3%5C%5C%28%5Csqrt%5B5%5D%7B3%5E%7B5x%2B2%7D%7D%29%5E5%3D%283%5E4%29%5E5%5C%5C3%5E%7B5x%2B2%7D%3D3%5E%7B4%5Ctimes5%7D%5C%5C3%5E%7B5x%2B2%7D%3D3%5E%7B20%7D%5C%5C%5Ctherefore%5C%5C5x%2B2%3D20%5C%5C5x%3D20-2%5C%5C5x%3D18%5C%5C%5Cboxed%7Bx%3D%5Cfrac%7B18%7D%7B5%7D%5Ctext%7B+atau+%7D3%5Cfrac%7B3%7D%7B5%7D%7D "(\frac{1}{3})^3\sqrt[5]{3^{5x+2}}=3\\\sqrt[5]{3^{5x+2}}=3\times3^3\\(\sqrt[5]{3^{5x+2}})^5=(3^4)^5\\3^{5x+2}=3^{4\times5}\\3^{5x+2}=3^{20}\\\therefore\\5x+2=20\\5x=20-2\\5x=18\\\boxed{x=\frac{18}{5}\text{ atau }3\frac{3}{5}}")
1 votes
Thanks 1
harryistiya
makasih kk .. tapi jawaban a sampai e lembaran : -1 0 1 2 3
izharulhaq78
ohh, maaf deh kalau gitu. saya tidak tahu jawabannya
harryistiya
y gpp kk mau gak tawaranku cek inbox kk
