Question

Jabarkan dan sederhanakan bentuk - bentuk aljabar berikut!

1.(y²+1/2)²=
2.(3a²+1/3)²=
3.(p²-4p)²=
4.(x²-5x)²=
5.2(-4a+3b)²=
6.3(-6p-7q)²=
7.(x+5)²+(x-3)²=
8.(3x+5)²-3(2x-7)²=
9.2(3x-6y)²+5(-x+y)²=

mohon jawabannya secepat mungkin terima kasih...

Answer 1

(y^2+1/2)(y^2+1/2)
= y^4+y^2+1

(2a^2+1/3)(2a^2+1/3)
= 4a^4+4/3a^2+2/3

(p^2-4p)(p^2-4p)
= p^4-8p^3+16p^2

(x^2-5x)(x^2-5x)
= x^4-10x^3+25x^2

2(-4a+3b)(-4a+3b)
= 2(16a^2-24ab+9b^2)
= 32a^2-48ab+18b^2

3(-6p-7q)(-6p-7q)
= 3(36p^2+84pq+49q^2)
= 108p^2+252pq+147

(x+5)(x+5)+(x-3)(x-3)
= (x^2+10x+25)+(x^2-6x+9)
= 2x^2+4x+34

(3x+5)(3x+5)-3(2x-7)(2x-7)
= (9x^2+30x+25)-3(4x^2-28x+49)
= (9x^2+30x+25)-(12x^2-84x+147)
= 9x^2+30x+25-12x^2+84x-147
= -3x^2+114x-122

2(3x-6)(3x-6)+5(-x+y)(-x+y)
= 2(9x^2-36x+36)+5(x^2-2xy+y^2)
= 18x^2-72x+72+5x^2-10xy+5y^2
= 23x^2-72x+72-10xy+5y^2