[tex]3-2x+1=x+\left(3x-2\right)\\-2x+3+1=x+\left(3x-2\right)\\-2x+4=x+\left(3x-2\right)\\-2x+4=x+3x-2\\-2x+4=4x-2\\-2x+4-4=4x-2-4\\-2x=4x-6\\-2x-4x=4x-6-4x\\-6x=-6\\\frac{-6x}{-6}=\frac{-6}{-6}\\x=1[/tex]
Respuesta:
3 - 2 x + 1 = X + (3 x - 2)
4 - 2 x = 3 x + X - 2
X = 6 - 5 x
-5 x - X + 6 = 0
-2 (x - 2) = 3 x + X - 2
x = (6 - X)/5
Explicación paso a paso:
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[tex]3-2x+1=x+\left(3x-2\right)\\-2x+3+1=x+\left(3x-2\right)\\-2x+4=x+\left(3x-2\right)\\-2x+4=x+3x-2\\-2x+4=4x-2\\-2x+4-4=4x-2-4\\-2x=4x-6\\-2x-4x=4x-6-4x\\-6x=-6\\\frac{-6x}{-6}=\frac{-6}{-6}\\x=1[/tex]
Respuesta:
3 - 2 x + 1 = X + (3 x - 2)
4 - 2 x = 3 x + X - 2
X = 6 - 5 x
-5 x - X + 6 = 0
-2 (x - 2) = 3 x + X - 2
X = 6 - 5 x
x = (6 - X)/5
Explicación paso a paso:
SALUDOS.