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f)
3+3(0,6+z)2z+6,6
3+1,8+z>o=2z+6,6
4,8-6,6=2z-z
z=-1,8 = 18/10 =9/5
f) x/3-2<1
x-6/3<1
x-6<3
x<9
Rpta: <-∞,9>
g) 3+3(0.6 + z) ≥ 2z + 6,6
3+1.8+3z≥2z+6,6
4,8+3z≥2z+6,6
3z-2z ≥ 6,6-4,8
z≥ 1.8
Rpta: [1.8,+∞>