Question

1. 5^0 + 4^0 + 3^0 + 2^0 - 1^0
2. (x^-2 y^8)^3
3. 32/3-√5
4. 9^10/6 x 9^1/3
5. 4√25^8
6. 3√125^2
7. (64)^5/6
8. (81)^1/4
9. (216)^2/3
10. 3^3 - 3^2
11. 2^4 - 2^3

pake caranya ya, pliis buat besok

Answer 1

1. 5^0 + 4^0 + 3^0 + 2^0 - 1^0 = 1 + 1 + 1 + 1 - 1 = 3
2. (x^-2 y^8)^3 = x^(-6).y^24
3. 32/3-√5 = 32/(3-√5) x (3+√5)/(3+√5)
                = 32(3-√5)/9-5
                = 32(3-√5)/4
                = 8(3-√5)
                = 24-8√5
 4. 9^10/6 x 9^1/3 = 9^(10/6+1/3) = 9^(5/3+1/3) = 9^2 = 81
 5. 4√25^8 = 25^(8/4) = 25^2 = 625
6. 3√125^2 = 125^(2/3) = (5^3)^2/3 = 5^2 = 25
7. (64)^5/6 = (2^6)^5/6 = 2^5 = 32
8. (81)^1/4 = (3^4)^1/4 = 3
9. (216)^2/3 = (6^3)^2/3 = 6^2 = 36
10. 3^3 - 3^2 = 27 - 9 = 18
11. 2^4 - 2^3 = 16 - 8 = 8