Respuesta:
∵∵∵[tex]\\ x^{2} \sqrt{x} \sqrt[n]{x} \sqrt[n]{x} \frac{x}{y} x_{123}[/tex]
Explicación paso a paso:
[tex]\lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \pi \sqrt[n]{x}[/tex]
[tex] \frac{15}{8} + \frac{2}{3} - 1 = \frac{37}{24} [/tex]
[tex]\boxed{HoLa}[/tex]
[tex] \frac{15}{8} + \frac{2}{3} - 1 = \\ \\ \frac{45}{24} + \frac{16}{24} - 1 = \\ \\ \frac{45 + 16}{24} - 1 = \\ \\ \frac{61}{24} - 1 = \\ \\ \frac{61}{24} - \frac{24}{24} = \\ \\ \frac{61 - 24}{24} = \\ \\ \frac{37}{24} [/tex]
Si te sirvió deja tu corona :)
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Respuesta:
∵∵∵[tex]\\ x^{2} \sqrt{x} \sqrt[n]{x} \sqrt[n]{x} \frac{x}{y} x_{123}[/tex]
Explicación paso a paso:
[tex]\lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \pi \sqrt[n]{x}[/tex]
[tex] \frac{15}{8} + \frac{2}{3} - 1 = \frac{37}{24} [/tex]
[tex]\boxed{HoLa}[/tex]
Explicación paso a paso:
[tex] \frac{15}{8} + \frac{2}{3} - 1 = \\ \\ \frac{45}{24} + \frac{16}{24} - 1 = \\ \\ \frac{45 + 16}{24} - 1 = \\ \\ \frac{61}{24} - 1 = \\ \\ \frac{61}{24} - \frac{24}{24} = \\ \\ \frac{61 - 24}{24} = \\ \\ \frac{37}{24} [/tex]
Si te sirvió deja tu corona :)