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2Fe + 3S → Fe₂S₃
2mole ------ 1 mol
112 g(bo 2 mole) ----------- 208g
11,2g( z zadania) ----------- X
X=20,8
masaFe= 56g
masa Fe₂S₃= 56g+56g+32g+32g+32g=208g
2H₂ + O₂ → 2H₂O
2 mole ----------- 2 mole
4g ------------ 36g (bo 2 mole)
200g ------------ X
X= 1800g
masa H=1g
masa H2O= 18 g