2.Zawartość procentowa wody w hydracie CuSO4 * xH2O wynosi 36%. Ustal wzór sumaryczny tego hydratu (mCu =64u, ms= 32u, m=16u, mu=1u).
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mCuSO4=160u
mH2O=18u
mCuSO4*xH2O=160u+x*18u
160+18x -------- 100%
18x -------------- 36%
18x*100 = 36(160+18x)
1800x = 5760+648x
1152x = 5760
x = 5
Wzór hydratu: CuSO4*5H2O