TENTUKANLAH HASIL PERKALIAN DAN PEMBAGIAN BENTU AKAR BERIKUT ! 1. √5 × √32. 2√13 × √9 3. 8√3 × 24√12.... Question from @kevinziggy93

September 2022 1 7 Report

TENTUKANLAH HASIL PERKALIAN DAN PEMBAGIAN BENTU AKAR BERIKUT !

1. √5 × √3
2. 2√13 × √9
3. 8√3 × 24√12
4. √6 ( 5 + √12 )
5. √16 / √2
6. √20 / 2√5
7. 70√8 / 5√2
8. √24 / √45
9. √9 / √2

YANG BISA JAWAB AKU KASIH JAWABAN TERCEDAS
PAKE CARA !

Ryzzx

Nomor 1

$\sqrt{5} \times \sqrt{3} \\ = \sqrt{5 \times 3} \\ = \sqrt{15}$

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Nomor 2

$2 \sqrt{13} \times \sqrt{9} \\ = 2 \sqrt{13} \times 3 \\ = (2 \times 3) \sqrt{13} \\ = 6 \sqrt{13}$

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Nomor 3

$8 \sqrt{3} \times 24 \sqrt{12} \\ = (8 \times 24) \times \sqrt{3 \times 12} \\ = 192 \times \sqrt{36} \\= 192 \times 6 \\ = 1.152$

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Nomor 4

$\sqrt{6} (5 + \sqrt{12} ) \\ = \sqrt{6} \times 5 + \sqrt{6 \times 12} \\ = 5 \sqrt{6} + \sqrt{72} \\ = 5 \sqrt{6} + \sqrt{36 \times 2} \\ = 5 \sqrt{6} + 6 \sqrt{2}$

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Nomor 5

$\frac{ \sqrt{16} }{ \sqrt{2} } \\ \\ = \sqrt{16 \div 2} \\ \\ = \sqrt{8} \\ \\ = \sqrt{4 \times 2} \\ \\ = 2 \sqrt{2}$

Nomor 6

$\frac{ \sqrt{20} }{2 \sqrt{5} } = \frac{ \sqrt{4 \times 5} }{2 \sqrt{5} } \\ \\ = \frac{2 \sqrt{5} }{2 \sqrt{5} } \\ \\ = 1$

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Nomor 7

$\frac{70 \sqrt{8} }{5 \sqrt{2} } \\ \\ = \frac{70}{5} \times \frac{ \sqrt{8} }{ \sqrt{2} } \\ \\ = 14 \times \sqrt{4} \\ \\ = 14 \times 2 \\ \\ = 28$

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Nomor 8

$\frac{ \sqrt{24} }{ \sqrt{45} } \\ \\ = \frac{ \sqrt{4 \times 6}}{ \sqrt{9 \times 5}} \\ \\ = \frac{2 \sqrt{6} }{3 \sqrt{5} } \\ \\ = \frac{2 \sqrt{6} }{3 \sqrt{5} } \times \frac{ \sqrt{5} }{ \sqrt{5} } \\ \\ = \frac{2 \sqrt{30} }{3 \times 5} \\ \\ = \frac{2 \sqrt{30} }{15}$