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2x+4y=30....(1)
x+y+10=0 atau
x=-y-10...(2)
substitusi (2) ke (10 diperoleh
2(-y-10)+4y=30
-2y-20+4y=30
2y=30+20
2y=50
y=25
substitusi y=25 ke (2) didapat
x=-25-10=-35
jadi, x=-35 dan y=25
x+y=-10 -> 15-2y+y=-10
15-y=-10 -> y=25
x+y+10=0 -> x+25+10=0 -> x+35=0 -> x=-35