ΗΘΙΑ 亗
procedimiento :
[tex]2(x+3)=5(x-1)[/tex]
[tex]2x+6=5x-5[/tex]
[tex]2x+6-6=5x-5-6[/tex]
[tex]2x=5x-11[/tex]
[tex]2x-5x=5x-11-5x[/tex]
[tex]-3x=-11[/tex]
[tex]\frac{-3x}{-3} =\frac{-11}{-3}[/tex]
[tex]x=\frac{11}{3}[/tex]
espero q te sirva :)
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Verified answer
ΗΘΙΑ 亗
procedimiento :
[tex]2(x+3)=5(x-1)[/tex]
[tex]2x+6=5x-5[/tex]
[tex]2x+6-6=5x-5-6[/tex]
[tex]2x=5x-11[/tex]
[tex]2x-5x=5x-11-5x[/tex]
[tex]-3x=-11[/tex]
[tex]\frac{-3x}{-3} =\frac{-11}{-3}[/tex]
[tex]x=\frac{11}{3}[/tex]
salu2!!
espero q te sirva :)