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a = 2 , b = -6, dan c = -2 gunakan rumus abc
X1,2 = -b +-√(b²-4ac)
2a
= 6 +-√((-6)²-4(2)(-2))
2(2)
= 6 +-√(36+16)
4
= 6 +-√52
4
= 6 +-2√13
4
= 3 +-√13
2
Jadi, x1 = 3 + √13 atau x2 = 3 - √13
2 2
atau (X + 3+√13)(X + 3-√13) = 0
2 2