∫(2x+1)^2 dx
= ∫(4x^2 + 4x + 1) dx
= 4/3 x^3 + 4/2 x^2 + x + c
= 4/3 x^3 + 2x^2 + x + c
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∫(2x+1)^2 dx
= ∫(4x^2 + 4x + 1) dx
= 4/3 x^3 + 4/2 x^2 + x + c
= 4/3 x^3 + 2x^2 + x + c