Question

Ditentukan x1 dan y1 memenuhi sistem persamaan linear 3x + 4y = 24 dan x - 2y =10.
Hitunglah nilai dari 1/2x1 + 2y1 !

Answer 1

3x+4y = 24 (x1) --> 3x+4y = 24
x-2y = 10 (x3) --> 3x-6y = 30 _
                             10y = -6
                                y = -6/10 = -3/5
x-2(-3/5) = 10
x+ 6/5 = 10
x = 10 - 6/5
x = 50/5 - 6/5
x = 44/5

1/2.x1+2y1 = 1/2.(44/5)+2.(-3/5)
                 = 22/5 -6/5
                 = 16/5

semoga membantu ya :)

Answer 2

3x+4y=24   x1
x-2y=10      x3

3x+4y=24
3x-6y=30  -
10y=-6
y= -6/10  =3/5

3x+4y=24   x1
x-2y=10     x2

3x+4y=24
2x-4y=20 +
5x=44
x=44/5

1/2x + 2y= (1/2 x 44/5) +2 (3/5)
=44/10+6/5
=44/10+12/10
=56/10=5,6