Question

( 2x - y + z ) a la dos

Answer 1

Simplificada:
(a+b+c)^2= (a^2)+(b^2)+(c^2)+(2ab)+(2ac)+(2bc)
Entonces

(2x^2)-(y^2)+(z^2)-(2*2xy)+(2*2xz)-(2yz)

(2x^2)-(y^2)+(z^2)-(4xy)+(4xz)-(2yz)