Question

2x - y = 1
(x - y)^2 = 0

Tentukan nilai dari x dan y!

Answer 1

2x - y -= 1
2x - 1 = y

(x - y)^2 = 0
(x - (2x-1))^2 = 0
(-x-1)^2 = 0
x^2 + 2x +1 = 0
(x+1) (x+1) = 0
x = -1

2x - y = 1
2(-1) - y = 1
-2 - y = 1
-y = 3
y = -3